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29f^2-47f=0
a = 29; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·29·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*29}=\frac{0}{58} =0 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*29}=\frac{94}{58} =1+18/29 $
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